Exception

You can't throw more than one exception at a time because throwing the exception unwinds current stack frame. Hence, after throw new DivideByZeroException() line execution, there is no more throw new IndexOutOfRangeException() line.

This may be a bit confusing to you, unless you understand how call stacks with exceptions work.

Imagince classical program without exceptions. Call stack looks like this:

function f (called from function g)
function g (called from main function)
function main

Now if we introduce try-catch blocks, then they are inserted into call stack. If function g has try-catch from within which it calls function f, then call stack looks like this:

1. function f (called from within try-catch from g)
2. catch block handling IndexOutOfRangeException - points to address in g function on which catch block begins
3. function g (called from try-catch from main function)
4. catch block handling DivideByZeroException - points to address in main function on which catch block begins
5. function main

Now if f throws DivideByZeroException, call stack unwinds - parts 1-3 are popped up and catch block for DivideByZeroException is reached. Then it is examined to find jump addres within main function, which actually handles the exception. After that block 4 is also popped up from stack, so that call stack looks like this:

function main

... and execution continues from the first line of catch block for DivideByZeroException.

As a result of this, line throw new IndexOutOfRangeException() cannot be reached.

Zoran