How to crop image

It seems like you are looking to crop an image in VB6 from the center at the bottom and specifically to a height of 30% from the bottom. Here's an outline of how you can achieve this:

1. Load the image into a PictureBox control in VB6.

2. Calculate the dimensions for cropping the image to 30% height from the bottom:

- Determine the original height of the image.

- Calculate 30% of the height to get the cropping height.

- Set the cropping rectangle starting from the center at the bottom with the calculated height.

3. Use the PaintPicture method in VB6 to crop and display the image in the PictureBox.

Below is a simplified example based on the steps mentioned above to guide you in VB6:

Private Sub Form_Load()
    Dim img As StdPicture
    Set img = LoadPicture("your_image_path.jpg") ' Load your image
    
    ' Calculate cropping dimensions
    Dim originalHeight As Long
    Dim cropHeight As Long
    
    originalHeight = img.Height
    cropHeight = originalHeight * 0.3 ' 30% of the original height
    
    ' Set the cropping rectangle (center at the bottom)
    Dim cropRect As RECT
    cropRect.Left = 0
    cropRect.Right = img.Width
    cropRect.Top = originalHeight - cropHeight
    cropRect.Bottom = originalHeight
    
    ' Crop and display the image in PictureBox1
    PictureBox1.AutoRedraw = True
    PictureBox1.PaintPicture img, 0, 0, img.Width, img.Height, cropRect.Left, cropRect.Top, cropRect.Right, cropRect.Bottom
    PictureBox1.Refresh
End Sub

Make sure to adjust the code to fit your specific requirements and image loading method in VB6.

I hope this helps you achieve the image cropping functionality you are looking for in VB6! If you have any further questions or need assistance with specific details, feel free to ask.