please tell how this program working, (sequence)? output?

Question

#include
#include
static int count;
int incr( ) {return ++count;}
int main( )
{
int arr[ ]={1, 2, 3, 4};
arr[count++]=incr( );
printf("arr[count]=%d
", arr[0]);
printf("arr[count]=%d
", arr[1]);
printf("arr[count]=%d
", arr[2]);
printf("arr[count]=%d
", arr[3]);
}

Sam Hobbs · Answer

Use the debugger to single-step through the program.
What you can also do to get help here is to describe what the program does as best as you can. If you have a specific question then ask about that. Since you are a student, the best help for you is to help you learn; it does not help you if you get all the answers from others.

Amit Kumar · Answer

first program output will be 2 2 3 4 how?

Marimuthu Arigovindasamy · Answer

Initiallt count = 0
because of this ++ in arr[count++]
count  = 1
count value again increasing by "return ++count"
count = 2
arr[2] means 3 (arr[0] = 1, arr[1] = 2)

Amit Kumar · Answer

how the output will be 3?
of this program
#include
#include
static int count;
int incr( ) {return ++count;}
int main( )
{
int arr[ ]={1, 2, 3, 4};
arr[count++]=incr( );
printf("arr[count]=%d
", arr[count]);