Reason for different o/p

Question

Following program reverses the i/p.
When you remove following code
Console.Write("Reverse number: ");
Console.Write(arrayChar);
and inserted following one
Console.Write("Reverse number: " + arrayChar);
o/p for whatever i/p is
Reverse number: System.Char[]
Please explain the reason for different o/p. Problem is highlighted.
using System;
class Program
{
static void Main()
{
Console.Write("Enter any number: ");
string s = Console.ReadLine();
char[] arrayChar = s.ToCharArray();
Array.Reverse(arrayChar);
Console.Write("Reverse number: ");
Console.Write(arrayChar);
Console.ReadLine();
}
}

Vulpes · Accepted Answer

Among its many overloads, Console.Write has an overload which takes a char[] argument. This overload simply prints the chars in the array, one after the other, to the console.
This is the overload which is being called in the above program.
However, when you remove these lines:
Console.Write("Reverse number: ");   Console.Write(arrayChar);
and insert this one in their place:
Console.Write("Reverse number: " + arrayChar);
you are now calling the overload of Console.Write which takes a single string argument.
This is because when you concatenate "Reverse number: " with arrayChar, the latter's Tostring() method is implicitly called. This method returns the name of arrayChar's type which is System.Char[]. So you therefore end up printing the following to the console:
Reverse number: System.Char[]

Answer

Thank you for your explanation.