Split an array like below dynamically.

Question

arr[]={ 1,2 ,3,4 , 5,6 ,6,7, 6,5 ,4,3, 7,8 ,8,8, 4,3 ,2, 8,6,5,3,4....n} split=2 sum=2 then the result array should be like this. res[0]=47 //1+2+5+6+6+5+7+8+4+3 res[1]=53 //3+4+6+7+4+3+8+8+2+8 Please help me to do this.   if split=3 sum=2 then  res[0]= 41   //1+2+6+7+7+8+2+8  res[2]= 45  //3+4+6+5+8+8+6+5  res[3]= 32 //5+6+4+3+4+3+3+4    res[] should be vary with split if split is 4 then res[4] should be also there.this should be  dynamically value of sum and split is vary between 1 to n.  please help me to do this. Thanks

Manas Mohapatra · Accepted Answer

Try with below code: static   void  Main( string [] args)   {        int [] arr = { 1, 2, 3, 4, 5, 6, 6, 7, 6, 5, 4, 3, 7, 8, 8, 8, 4, 3, 2, 8 };        int  spliter = 2; // Take it from console         int [] tempArr =  new   int [spliter];           int  index = 0;        while  (index      {            for  ( int  idx = 0; idx          {                  tempArr[idx] += arr.Skip(index).Take(2).Sum();               index += 2;           }       }           for  ( int  idx = 0; idx      {           Console.WriteLine((idx + 1) +  " value is: "  + tempArr[idx]);       }   }

Midhun Tp · Answer

Hi Pruthvi,
Please try below code -
int[] arr = { 1, 2, 3, 4, 5, 6, 6, 7, 6, 5, 4, 3, 7, 8, 8, 8, 4, 3, 2, 8, 6, 5, 3, 4 }; int split = 3; int sum = 2; int[] res = new int[split]; int i = 0; int j = 1; for (int k = 0; k { res[i % split] = res[i % split] + arr[k]; if (k == ((j * sum) - 1)) { j++; i++; } }

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Split an array like below dynamically.

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