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Given an even-sized integer array, divide the array into two equal halves. A pair (i, j) is considered a dominant pair if i belongs to the first half, j belongs to the second half, and arr[i] >= 5 × arr[j]. The goal is to count the total number of dominant pairs efficiently. A brute-force approach takes O(n²) time. By sorting both halves independently and using the two-pointer technique, we can solve the problem in O(n log n) time. This problem is a good example of how sorting can optimize pair-counting problems by avoiding unnecessary comparisons.
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